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<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>JSONP 实例</title>
<script src="https://cdn.staticfile.org/jquery/1.8.3/jquery.js"></script>
</head>
<body>
<div id="divCustomers"></div>
</body>
</html>
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$.getJSON("https://www.runcodex.com/try/ajax/jsonp.php?jsoncallback=?", function(data) {
var html = '<ul>';
for(var i = 0; i < data.length; i++)
{
html += '<li>' + data[i] + '</li>';
}
html += '</ul>';
$('#divCustomers').html(html);
});
输入 CSS 代码……
